Homework Clinic
Mathematics Clinic => Grade 9 Mathematics => Topic started by: curlz on Oct 3, 2013
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I need the exact formula & how to work it for this problem: A sample of neon gas has a volume of 2.50L and a temperature of 15 degrees Celsius. What is the new temperature in degrees when the volume of the sample is changed to 1250 mL?
Thanks!
Thanks for everyone's help!!! I had the basic formula, but didn't know how to rearrange. Thanks!
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formula: V1/T1=V2/T2
want: T2
know: 1000 mL = 1 L
step 1: convert mL to L
step 2: rearrange formula and solve for T2
step 3: ANS
good luck.
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Charles's Law---->V1/T1=V2/T2
or volume1 over temperature1--equals--volume2 over Temperature2
Volume1 = 2.50
Temperature1 = 15C
Volume2 = 1250mL
Temperature2 = ???
ok first get your units in order...volume has to always be in Liters and temperature always in Kelvins
Volume2 = 1250mL divided by 1000L equals 1.25 so----> volume2 is 1.25L
Temperature1 = 15C + 273K = 288Kelvins
now as you can notice since the volume decreases the temperature increases (they are directly proportional to each other)
2.50L/288K == 1.25L/T2 ---> cross multiply then divide 2.50L from each side because you just want T2
in the end it looks like this-----> T2 =(1.25L) x (288K) / 2.50L ---> giving a temperature of 144K