Question 1
Question 2
Answer 1
0.930°C = 1.86°C/m* (nmol/0.2500 kg);n= 0.125 mol
molar mass = 22.5 g/0.125 mol = 180. g/mol
empirical mass CH2O = 30.0;n= 180/30.0 = 6
molecular formula = 6(CH2O) = C6H12O6
Answer 2
1.5m= 1.5 mol C2H5OH/1.0 kg water
1.5 mol * 46.07 g/mol = 69 g ethanol
69/(1000 + 69) = 6.5%