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Author Question: A father wishes to distribute 19 pieces of candy among his 4 children (Abe, Betty, Cindy, and Dale) ... (Read 580 times)

cool

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on: May 5, 2020
A father wishes to distribute 19 pieces of candy among his 4 children (Abe, Betty, Cindy, and Dale) based on the number of hours each child spends doing chores around the house. Using a certain apportionment method, he has determined that Abe is to get 9 pieces of candy, Betty is to get 4 pieces, Cindy is to get 3 pieces, and Dale is to get 3 pieces. However, just before he hands out the candy, he discovers that he has 20 pieces (not 19) of candy. When he apportions the 20 pieces of candy using the same apportionment method, Abe ends up with 10 pieces, Betty with 5 pieces, Cindy with 3 pieces, and Dale with 2 pieces. This is an example of
◦ the population paradox.
◦ a violation of the quota rule.
◦ the Alabama paradox.
◦ the new states paradox.
◦ none of these
Excursions in Modern Mathematics ¦ Tannenbaum ¦ 9th Edition
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Marked as best answer by cool on May 5, 2020

bdobbins

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Reply #1 on: May 5, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Shifty Mic-

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Reply #2 on: Nov 8, 2021
Thank you


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