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Author Question: The figure shown here shows a rectangle inscribed in an isosceles right triangle ... (Read 146 times)

Lisaclaire

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on: Feb 28, 2021

Question 1

Solve the problem.

A right triangle has one vertex on the graph of y = x2 at (x, y), another at the origin, and the third on the (positive) y-axis at (0, y). Express the area A of the triangle as a function of x.

Question 2

Solve the problem.

The figure shown here shows a rectangle inscribed in an isosceles right triangle whose hypotenuse is 8 units long. Express the area A of the rectangle in terms of x.

◦ A(x) = 2x(x - 4)
◦ A(x) = 2x2
◦ A(x) = x(4 - x)
◦ A(x) = 2x(4 - x)
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by Lisaclaire on Feb 28, 2021

Dnite

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Lisaclaire

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Reply 2 on: Feb 28, 2021
Thanks for the timely response, appreciate it

covalentbond

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Reply 3 on: Yesterday
Excellent

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