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Author Question: Complete combustion of a 0.500 g sample of a pure hydrocarbon yielded 0.973 g CO2 and 0.319 g H2O. ... (Read 265 times)

erika

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on: Jul 8, 2021

Question 1

Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of CO2 and 0.1451 g of H2O. What is the empirical formula of the compound?
◦ CH2
◦ C2H5
◦ C4H10
◦ C5H2

Question 2

Complete combustion of a 0.500 g sample of a pure hydrocarbon yielded 0.973 g CO2 and 0.319 g H2O. The empirical formula of this hydrocarbon is ________.
◦ C3H5
◦ C2H3
◦ C4H6
◦ C5H8
◦ C6H9
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by erika on Jul 8, 2021

meganlapinski

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Natalie Sodowich

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Reply #2 on: Sep 20, 2022
Ty


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