Question 1
Consider the titration of 100.0 mL of 0.10 M H2A (Ka1 = 1.5 × 10–4; Ka2 = 8.0 × 10–7) with 0.20 M NaOH. Calculate the volume of 0.20 M NaOH required to reach an [H+] of 6.0 × 10–4M.
◦
0 mL◦
10. mL◦
25. mL◦
50. mL◦
65. mLQuestion 2
Consider the titration of 100.0 mL of 0.10 M H2A (Ka1 = 1.50 × 10–4; Ka2 = 7.82 × 10–7) with 0.20 M NaOH. Calculate the [H+] after 75.0 mL of 0.20 M NaOH has been added.
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1.6 × 10–6M◦
1.3 × 10–8M◦
3.9 × 10–7M◦
7.8 × 10–7M◦
None of these are correct.