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Author Question: Arrange the following in order from most oxidized to least oxidized. (Read 1340 times)

bcretired

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on: Nov 18, 2019

Question 1

Find the suitable base for the following reaction:

C6H5OH + :B → C6H5O:- + H:B+

The pKa for C6H5OH (phenol) is 9.88. The formula for the base is followed by the pKa of its conjugate acid.
◦ OH-, pKa = 15.73
◦ CN-, pKa = 9.31
◦ CH3C(=O)CH3, pKa = -7.2
◦ CF3COO-, pKa = 0.23
◦ CH3COO-, pKa = 4.74

Question 2

Arrange the following in order from most oxidized to least oxidized.



◦ III > I > II
◦ II > I > III
◦ II > III > I
◦ I > II > III
◦ III > II > I
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Marked as best answer by bcretired on Nov 18, 2019

Tabitha_2016

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Finn Copeland

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Reply #2 on: Feb 6, 2020
thank


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Reply #3 on: Jan 31, 2021
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