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Author Question: The reaction is first order in N2O5. For this reaction at 45oC, the rate constant k = 1.0 105 s1, ... (Read 34 times)

Ebrown

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on: Mar 21, 2021

Question 1

The reaction

   

exhibits the rate law

   

where k = 1.0 × 10–5M–1 s–1 at 25°C. This reaction is run where the initial concentration of NOBr ([NOBr]0) is 0.40 M. What is one half-life for this experiment?


◦ 4.0 s
◦ 2.0 × 10–5 s
◦ 6.9 × 10–4 s
◦ 2.5 × 105 s
◦ None of these are correct.

Question 2

The reaction
   
is first order in N2O5. For this reaction at 45oC, the rate constant k = 1.0 × 10–5 s–1, where the rate law is defined as
   
For a particular experiment ([N2O5]0 = 1.0 × 10–3M), calculate [N2O5] after 4.1 × 105 seconds.

◦ 4.1 M
◦ 1.0 × 10–3M
◦ 1.7 × 10–5M
◦ 0 M
◦ 11 M
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by Ebrown on Mar 21, 2021

Gabe

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Ebrown

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Reply 2 on: Mar 21, 2021
Gracias!

ryhom

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Reply 3 on: Yesterday
:D TYSM

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