Question 1
Consider the titration of 100.0 mL of 0.100 M H2A (Ka1 = 1.50 × 10–4; Ka2 = 1.00 × 10–8). How many milliliters of 0.100 M NaOH must be added to reach a pH of 5.000?
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41.9 mL◦
93.8 mL◦
100. mL◦
200. mL◦
60.0 mLQuestion 2
Consider the titration of 100.0 mL of 0.250 M aniline (Kb = 3.8 × 10–10) with 0.500 M HCl. For calculating the volume of HCl required to reach a pH of 8.0, which of the following expressions is correct? (x = volume in mL of HCl required to reach a pH of 8.0)
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= [aniline]◦
[H+] = x◦
= [aniline]◦
= [aniline]◦
None of these are correct.