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Mathematics Clinic => Other Maths => Topic started by: cool on May 5, 2020

Title: A father wishes to distribute 19 pieces of candy among his 4 children (Abe, Betty, Cindy, and Dale) ...
Post by: cool on May 5, 2020
A father wishes to distribute 19 pieces of candy among his 4 children (Abe, Betty, Cindy, and Dale) based on the number of hours each child spends doing chores around the house. Using a certain apportionment method, he has determined that Abe is to get 9 pieces of candy, Betty is to get 4 pieces, Cindy is to get 3 pieces, and Dale is to get 3 pieces. However, just before he hands out the candy, he discovers that he has 20 pieces (not 19) of candy. When he apportions the 20 pieces of candy using the same apportionment method, Abe ends up with 10 pieces, Betty with 5 pieces, Cindy with 3 pieces, and Dale with 2 pieces. This is an example of
◦ the population paradox.
◦ a violation of the quota rule.
◦ the Alabama paradox.
◦ the new states paradox.
◦ none of these
Title: A father wishes to distribute 19 pieces of candy among his 4 children (Abe, Betty, Cindy, and Dale) ...
Post by: bdobbins on May 5, 2020
the Alabama paradox.
Title: Re: A father wishes to distribute 19 pieces of candy among his 4 children (Abe, Betty, Cindy, and Da
Post by: Shifty Mic- on Nov 8, 2021
Thank you