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Author Question: A 0.0925 g sample of a monoprotic base (mm = 17.03 g/mol) was dissolved in water to produce 100 mL ... (Read 669 times)

elizabeth18

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Question 1

0.653 g of a monoprotic acid (MW= 157 g/mol) is dissolved in water to produce 50.0 mL of a solution with pH = 2.13. Determine the ionization constant of the acid.
◦ 7.9 × 10-3
◦ 8.9 × 10-2
◦ 6.6 × 10-4
◦ 3.9 × 10-2
◦ 3.6 × 10-6

Question 2

A 0.0925 g sample of a monoprotic base (mm = 17.03 g/mol) was dissolved in water to produce 100 mL of solution with a pH = 11.00.  What is the ionization constant of this base?
◦ 1.8 × 10-6
◦ 1.8 × 10-11
◦ 1.8 × 10-21
◦ 1.8 × 10-5
◦ 1.1 × 10-6


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Marked as best answer by elizabeth18 on Jul 8, 2021

1_Step_At_ATime

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