Charles's Law - How to calculate temperature when volume ...

[curlz]

I need the exact formula & how to work it for this problem: A sample of neon gas has a volume of 2.50L and a temperature of 15 degrees Celsius. What is the new temperature in degrees when the volume of the sample is changed to 1250 mL?

Thanks!
Thanks for everyone's help!!! I had the basic formula, but didn't know how to rearrange. Thanks!

[TI]

formula:  V1/T1=V2/T2
want:  T2
know:  1000 mL = 1 L

step 1:  convert mL to L
step 2:  rearrange formula and solve for T2
step 3:  ANS

good luck.

[Hawke]

Charles's Law---->V1/T1=V2/T2
or volume1 over temperature1--equals--volume2 over Temperature2

Volume1 = 2.50
Temperature1 = 15C

Volume2 = 1250mL
Temperature2 =

ok first get your units in order...volume has to always be in Liters and temperature always in Kelvins

Volume2 =  1250mL divided by 1000L  equals  1.25 so----> volume2 is 1.25L
Temperature1 = 15C + 273K = 288Kelvins

now as you can notice since the volume decreases the temperature increases (they are directly proportional to each other)

2.50L/288K == 1.25L/T2 ---> cross multiply then divide 2.50L from each side because you just want T2

in the end it looks like this-----> T2 =(1.25L) x (288K) / 2.50L   ---> giving a temperature of  144K