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Consider the titration of 100.0 mL of 0.10 M H2A (Ka1 = 1.50 104; Ka2 = 7.82 107) with 0.20 M ...

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karlynnae:
Question 1Consider the titration of 100.0 mL of 0.10 M H2A (Ka1 = 1.5 × 10–4; Ka2 = 8.0 × 10–7) with 0.20 M NaOH. Calculate the volume of 0.20 M NaOH required to reach an [H+] of 6.0 × 10–4M.
◦ 0 mL
◦ 10. mL
◦ 25. mL
◦ 50. mL
◦ 65. mL

Question 2Consider the titration of 100.0 mL of 0.10 M H2A (Ka1 = 1.50 × 10–4; Ka2 = 7.82 × 10–7) with 0.20 M NaOH. Calculate the [H+] after 75.0 mL of 0.20 M NaOH has been added.
◦ 1.6 × 10–6M
◦ 1.3 × 10–8M
◦ 3.9 × 10–7M
◦ 7.8 × 10–7M
◦ None of these are correct.

Alyson.hiatt@yahoo.com:
Answer 110. mL

Answer 27.8 × 10–7M

Ruohan Liu:
Thank you！！

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