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Author Question: Under certain conditions the reaction H2O2 + 3I- + 2H+ I3- + 2H2O occurs by the following series of ... (Read 298 times)

lindiwe

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on: Mar 21, 2021
Under certain conditions the reaction H2O2 + 3I- + 2H+→ I3- + 2H2O occurs by the following series of steps:
 
k1
 
Step 1.
 
H2O2 + H+H3O2+
 
k-1
 
Step 2.
 
H3O2+ + I-→ H2O + HOI
(slow, rate constant k2)
 
Step 3.
 
HOI + I-→ OH- + I2
(fast, rate constant k3)
 
Step 4.
 
OH- + H+→ H2O
(fast, rate constant k4)
 
 
Step 5.
 
I2 + I-→ I3-
(fast, rate constant k5)

​

The rate law for the reaction would be:

 
Reference: Ref 12-17

​

​


◦ Δ[I3]/Δt = k[H2O2]
◦ Δ[I3]/Δt = k[H2O2][H+][I-]
◦ Δ[I3]/Δt = k[H2O2][H+]
◦ Δ[I3]/Δt = k[H2O2][I-]
◦ Δ[I3]/Δt = k[H2O2][H+]2[I-]-3

​

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Marked as best answer by lindiwe on Mar 21, 2021

chevyboi1976

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Aaron Vallejo

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Reply #2 on: Jul 18, 2021
thank you


Zimo Han

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Reply #3 on: Feb 13, 2022
thank you


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