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Author Question: Under certain conditions the reaction H2O2 + 3I- + 2H+ I3- + 2H2O occurs by the following series of ... (Read 299 times)

lindiwe

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Under certain conditions the reaction H2O2 + 3I- + 2H+→ I3- + 2H2O occurs by the following series of steps:
 
k1
 
Step 1.
 
H2O2 + H+H3O2+
 
k-1
 
Step 2.
 
H3O2+ + I-→ H2O + HOI
(slow, rate constant k2)
 
Step 3.
 
HOI + I-→ OH- + I2
(fast, rate constant k3)
 
Step 4.
 
OH- + H+→ H2O
(fast, rate constant k4)
 
 
Step 5.
 
I2 + I-→ I3-
(fast, rate constant k5)

The rate law for the reaction would be:

 
Reference: Ref 12-17


Δ[I3]/Δt = k[H2O2]
Δ[I3]/Δt = k[H2O2][H+][I-]
Δ[I3]/Δt = k[H2O2][H+]
Δ[I3]/Δt = k[H2O2][I-]
Δ[I3]/Δt = k[H2O2][H+]2[I-]-3



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Marked as best answer by lindiwe on Mar 21, 2021

chevyboi1976

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