Homework Clinic
Science Clinic => Chemistry => Topic started by: londonang on Nov 18, 2019
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Question 1
Give the approximate bond angle between two equatorial positions for a molecule with a trigonal bipyramidal geometry.
◦ 109.5°
◦ 180°
◦ 120°
◦ 105°
◦ 90°
Question 2
Determine the electron geometry (eg) and molecular geometry (mg) of BCl3.
◦ eg = trigonal planar, mg = trigonal planar
◦ eg = tetrahedral, mg = trigonal planar
◦ eg = trigonal bipyramidal, mg = trigonal bipyramidal
◦ eg = trigonal planar, mg = bent
◦ eg = tetrahedral, mg = trigonal pyramidal
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Answer 1
120°
Answer 2
eg = trigonal planar, mg = trigonal planar