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Science Clinic => Chemistry => Topic started by: laurencescou on Nov 18, 2019

Title: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal ...
Post by: laurencescou on Nov 18, 2019

Question 1

If 8.32 g of copper is mixed with 5.2372 × 10-2 mol of zinc to create the alloy brass, how many metal atoms total are present in the brass?
◦ 1.10 × 1023 metal atoms
◦ 7.88 × 1022 metal atoms
◦ 3.04 × 10-25 metal atoms
◦ 3.15 × 1022 metal atoms
◦ 3.15 × 10-22 metal atoms

Question 2

If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal are present in the pewter?
◦ 0.6233 mol total
◦ 1.037 mol total
◦ 1.604 mol total
◦ 0.8675 mol total
◦ 0.9643 mol total

Title: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal ...
Post by: blazinlyss on Nov 18, 2019

Answer 1

1.10 × 1023 metal atoms

Answer 2

1.037 mol total

Title: Re: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of m
Post by: ghassan2271 on Feb 14, 2022

Thank you!

Title: Re: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of m
Post by: Hareeshwar Suresh on Feb 28, 2022

Thank you

Title: Re: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of m
Post by: Jake Sint on Apr 27, 2022

Thank You

Title: Re: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of m
Post by: ruth oderinde on May 27, 2022

thank you