Question 1
At 1.0133 bar, the heat of sublimation of gallium is 277 kJ mol-1 and the heat of vaporization is 271 kJ mol-1. To the correct number of significant figures, how much heat is required to melt 5.50 mol of gallium at 1.0133 bar?Question 2
How much heat is absorbed/released when 40.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) according to the following chemical equation?4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l) | Δ rH° = 1168 kJ |
Answer 1
33 kJAnswer 2
685.8 kJ of heat are absorbed.