Homework Clinic
Mathematics Clinic => Grade 10 Mathematics => Topic started by: curlz on Jun 18, 2013
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1. How would I solve the using the quadratic formula? 4x² - 12x + 7 = 0
2. What would be the equation of the quadratic function with zeroes 2 and 6 and a vertex at (4,4)
3. With the parent function y = x² what would be the equation that shift the function 5 units right and 3 units up?
4. With the parent function y = ?x what would be the equation that vertically stretch the function by a factor of 5 and it 4 units down?
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1.- x= (12 +- sqrt (144-112))/8 x= (12+- sqrt(32))/8
2.- a parabola (Simetrical w/respect Y axis) ) y-k =4p(x-h)^2 (h,k ) vertex , p focus distance
y-4 =4p(x-4) ^2 if x=2 y=0 , -4=4p(2-4)^2 , p= - 1/4
y-4= -1(x-4)^2 since p<0 parabola has arms down .-
3.- Y=X^2 has vertex in (0,0) .- You must shift the vertex coodinates 5 y 3
Y-3 = (X-5 ) ^2 .-
4.- Y^2 =X ( Horizontal parabola ) It has the general form
(y-k)^2 =4p ( x-h)
If you want to close it arms you must act on p .- in your case 4p=1 or p=1/4
If you want close p 5 times then p=(1/4 ) /5 =1/20 and 4p= 1/5
(Y-0)^2 = 1/5 (X-0) , Y^2= 1/5 X