Author Question: What is the Vertex, Axis of symmetry and the roots to X^2+2-3X? (Read 1477 times)


TI

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for quadratics:

x = -b/2a

x = -(-3) / 2(1)

x = 3/2 <- the axis of symmetry

to find the vertex, plug this x value into the equation:

y = (3/2)^2 + 2 - 3(3/2)

= 9/4 + 8/4 - 18/4
= -1/4

vertex = (3/2, -1/4)

for roots find what multiplies to get 2 and adds to get -3

that's -1,-2

so the roots are x = 1 and x = 2



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