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Science Clinic => Chemistry => Topic started by: bvyeehaw on Nov 5, 2023

Title: Find the concentration of Pb2+ ions in a solution made by adding 5.00 g of lead(II) iodide to 500. ...
Post by: bvyeehaw on Nov 5, 2023

Question 1

Find the concentration of calcium ions in a solution made by adding 3.50 g of calcium fluoride to 750. mL of 0.125 M NaF.  [For CaF₂, K_sp = 3.95 × 10^–11.]
◦ 3.16 × 10^–10 M
◦ 2.53 × 10^–9 M
◦ 4.29 × 10^–4 M
◦ 6.32 × 10^–10 M
◦ 2.15 × 10^–4 M

Question 2

Find the concentration of Pb²⁺ ions in a solution made by adding 5.00 g of lead(II) iodide to 500. mL of 0.150 M KI.  [For PbI₂, K_sp = 1.39 × 10^–8.]
◦ 3.04 × 10^–4 M
◦ 1.54 × 10^–7 M
◦ 6.18 × 10^–7 M
◦ 1.52 × 10^–4 M
◦ 9.27 × 10^–8 M

Title: Find the concentration of Pb2+ ions in a solution made by adding 5.00 g of lead(II) iodide to 500. ...
Post by: dianagarcia on Nov 5, 2023

Answer 1

2.53 × 10^–9 M

Answer 2

6.18 × 10^–7 M