Author Question: A BASE jumper's velocity (in meters per second) after t seconds is given by where m is the mass of ... (Read 97 times)

xroflmao · **on:** Dec 18, 2021

A BASE jumper's velocity (in meters per second) after t seconds is given by

where m is the mass of the object in kilograms, g = 9.8 m/s² is the acceleration due to gravity, and k is a physical constant. How fast is the BASE jumper falling at the end of a 12 second delay? Use

and

Round the answer to one decimal place if necessary.
◦ 58.2 m/s
◦ 698 m/s
◦ 63.2 m/s
◦ 19.2 m/s

meltdown117 · **Reply #1 on:** Dec 18, 2021

A FREE account is required to view all solutions!

Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

Answer Preview

Only 25% of students answer this correctly