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Author Question: For the reaction C6H14(g) C6H6(g) + 4H2(g), P(H2)/t was found to be 2.5 102 atm/s, where P(H2) is ... (Read 48 times)

jmoore1989

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on: Nov 5, 2023
For the reaction C6H14(g) → C6H6(g) + 4H2(g), ΔP(H2)/Δt  was found to be 2.5 × 10–2 atm/s, where ΔP(H2) is the change in pressure of hydrogen.  Determine ΔP(C6H14)/Δt for this reaction at the same time.
◦ 2.5 × 10–2 atm/s
◦ –6.2 × 10–3 atm/s
◦ –2.5 × 10–2 atm/s
◦ 0.10 atm/s
◦ 6.2 × 10–3 atm/s
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by jmoore1989 on Nov 5, 2023

dianagarcia

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jmoore1989

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Reply 2 on: Nov 5, 2023
Wow, this really help

cassie_ragen

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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