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Author Question: Given a sphere with center (20,30,50) and a second sphere with center (10,25,-20), what is the ... (Read 147 times)

mpobi80

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on: Oct 14, 2019

Question 1

To avoid false collisions when using bounding circles, you could take the extra step of:


◦

calculating the distance between the centers to at least the 4th decimal place.


◦

using additional smaller circles.


◦

squaring both the distance between the centers and the sum of the radii.


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None of the above.



Question 2

Given a sphere with center (20,30,50) and a second sphere with center (10,25,-20), what is the greatest distance at which a collision will occur?


◦

1025


◦

≈70.88


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5025


◦

≈32.02

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Marked as best answer by mpobi80 on Oct 14, 2019

TINA

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Reply #1 on: Oct 14, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mpobi80

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Reply 2 on: Oct 14, 2019
YES! Correct, THANKS for helping me on my review

kilada

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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