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Author Question: Suppose ArrayList x contains two strings [Beijing, Singapore]. Which of the following method will ... (Read 30 times)

abern

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on: May 6, 2020

Question 1

Suppose ArrayList x contains two strings [Beijing, Singapore]. Which of the following methods will cause the list to become [Beijing, Chicago, Singapore]?
◦ x.add(1, "Chicago")
◦ x.add(0, "Chicago")
◦ x.add(2, "Chicago")
◦ x.add("Chicago")

Question 2

Suppose ArrayList x contains two strings [Beijing, Singapore]. Which of the following method will cause the list to become [Beijing]?
◦ x.remove(0)
◦ x.remove("Singapore")
◦ x.remove(2)
◦ x.remove(1)
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Marked as best answer by abern on May 6, 2020

Galvarado142

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Reply #1 on: May 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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abern

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Reply 2 on: May 6, 2020
Great answer, keep it coming :)

emsimon14

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Reply 3 on: Yesterday
Wow, this really help

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