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Author Question: The following questions refer to the following system: 500.0 mL of 0.020 M Mn(NO3)2 are mixed with ... (Read 56 times)

big1devin

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on: Mar 21, 2021
The following questions refer to the following system: 500.0 mL of 0.020 M Mn(NO3)2 are mixed with 1.0 L of 1.0 M Na2C2O4. The oxalate ion, C2O4, acts as a ligand to form a complex ion with the Mn2+ ion with a coordination number of two.
 
Mn2+ + C2O42- MnC2O4
 
K1 = 7.9 × 103
 
[Mn(C2O4)2]2- MnC2O4 + C2O42-
 
K2 = 1.26 × 10-2

​

Find the equilibrium concentration of the Mn2+ion.


 
Reference: Ref 16-2

​

​


◦ 9.2 × 10-5M
◦ 0.01 M
◦ 2.5 × 10-8M
◦ 1.3 × 10-4M
◦ 6.7 × 10-3M
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by big1devin on Mar 21, 2021

alvinum

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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big1devin

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Reply 2 on: Mar 21, 2021
Thanks for the timely response, appreciate it

amit

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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