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Author Question: Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The ... (Read 53 times)

cdr_15

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Question 1

A solution is prepared by dissolving 21.0 g of glycerin (C3H8O3) in 201 g of ethanol The freezing point of the solution is ________°C. The freezing point of pure ethanol is . The molal freezing point depression constant (Kf) for ethanol is The molar masses of glycerin and of ethanol are 92.1 g mol-1 and 46.1 g mol-1, respectively.
◦ -116.4
◦ -112.3
◦ -116.9
◦ 2.26
◦ -112.8

Question 2

Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal freezing point depression constant (Kf) for water is
◦ +0.45 °C
◦ 1.23 °C
◦ -0.23 °C
◦ +0.23 °C
◦ -0.45 °C


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Marked as best answer by cdr_15 on Nov 18, 2019

huda

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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cdr_15

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Reply 2 on: Nov 18, 2019
Thanks for the timely response, appreciate it


cdmart10

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Reply 3 on: Yesterday
:D TYSM

 

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