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Author Question: Why can't chromium and nickel form a miscible solid solution over the entire composition range? (Read 126 times)

jayhills49

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Question 1

Which of the following is TRUE concerning substitutional alloys?
◦ Titanium carbide is an example of a substitutional alloy.
◦ The metals forming a substitutional alloy must have very different electronegativities.
◦ The metals involved must have similar radii.
◦ One type of metal atom is inserted in between the metal atoms in the initial crystal structure of the other metal.
◦ The two metals must be miscible over the entire composition range.

Question 2

Why can't chromium and nickel form a miscible solid solution over the entire composition range?
◦ The lever rule says that these two metals can't coexist in an alloy.
◦ The octahedral holes in the chromium crystal are not large enough to accommodate the nickel.
◦ The tetrahedral holes in the nickel crystal are not large enough to accommodate the chromium.
◦ The two metals crystallize into different cubic structures in their pure forms.
◦ Chromium atoms can only fit inside tetrahedral holes, which are not present in the structure of pure nickel.


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Marked as best answer by jayhills49 on Nov 18, 2019

popopong

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jayhills49

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)


alvinum

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Reply 3 on: Yesterday
Wow, this really help

 

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