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Author Question: How much heat is absorbed/released when 40.00 g of NH3(g) reacts in the presence of excess O2(g) to ... (Read 263 times)

imanialler

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Question 1

At 1.0133 bar, the heat of sublimation of gallium is 277 kJ mol-1 and the heat of vaporization is 271 kJ mol-1. To the correct number of significant figures, how much heat is required to melt 5.50 mol of gallium at 1.0133 bar?
◦ 33 kJ
◦ 6 kJ
◦ 244 kJ
◦ 274 kJ

Question 2

How much heat is absorbed/released when 40.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) according to the following chemical equation?

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)

Δ

rH° = 1168 kJ

◦ 685.8 kJ of heat are absorbed.
◦ 2743 kJ of heat are released.
◦ 2743 kJ of heat are absorbed.
◦ 685.8 kJ of heat are released.


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Marked as best answer by imanialler on Nov 18, 2019

nixon_s

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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