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Author Question: The second-order reaction 2 Mn(CO)5 Mn2(CO)10 has a rate constant equal to 3.0 109 L mol-1 s-1 at ... (Read 102 times)

londonang

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on: Jul 8, 2021
The second-order reaction 2 Mn(CO)5→ Mn2(CO)10 has a rate constant equal to 3.0 × 109 L mol-1 s-1 at 25 °C. If the initial concentration of Mn(CO)5 is 2.0 × 10-5 mol L-1, how long will it take for 90.% of the reactant to disappear?
◦ 6.7 × 10-16 s
◦ 7.4 × 10-15 s
◦ 1.5 × 10-4 s
◦ 6.0 × 103 s
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by londonang on Jul 8, 2021

emilymalinowski12

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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londonang

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Reply 2 on: Jul 8, 2021
Excellent

raenoj

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Reply 3 on: Yesterday
Gracias!

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