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Author Question: Select an appropriate synthetic route for the equation given. (Read 57 times)

wqwpfwpoefnpwenf

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on: Feb 17, 2022
Select an appropriate synthetic route for the equation given.



◦

1. NaNH2; 2. CH3Br; 3. NaNH2; 4. CH3Br; 5. Na, NH3 (l); 6. RCO3H


◦ 1. MCPBA; 2. CH3Br r; 3. NaNH2; 4. CH3Br; 5. OsO4; 6. H3O+
◦ 2. CH3Br; 2. NaNH2; 3. CH3Br; 4. Na, NH3(l); 5. RCO3H
◦ 1. MCPBA; 2. CH3Br; 3. NaNH2; 4. CH3Br; 5. Na, NH3(l); 6. RCO3H
◦

1. NaNH2; 2. CH3Br; 3. NaNH2; 4. CH3Br; 5. OsO4; 6. H3O+

Organic Chemistry ¦ Klein ¦ 4th Edition
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Marked as best answer by wqwpfwpoefnpwenf on Feb 17, 2022

ElaneShive

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Reply #1 on: Feb 17, 2022
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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wqwpfwpoefnpwenf

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Reply 2 on: Feb 17, 2022
Great answer, keep it coming :)

ecabral0

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Reply 3 on: Yesterday
Excellent

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