Consider the titration of 100.0 mL of 0.10 M H2A (Ka1 = 1.50 ...

[karlynnae]

Question 1

Consider the titration of 100.0 mL of 0.10 M H₂A (K_a1 = 1.5 × 10^–4; K_a2 = 8.0 × 10^–7) with 0.20 M NaOH. Calculate the volume of 0.20 M NaOH required to reach an [H⁺] of 6.0 × 10^–4M.

◦ 0 mL
◦ 10. mL
◦ 25. mL
◦ 50. mL
◦ 65. mL

Question 2

Consider the titration of 100.0 mL of 0.10 M H₂A (K_a1 = 1.50 × 10^–4; K_a2 = 7.82 × 10^–7) with 0.20 M NaOH. Calculate the [H⁺] after 75.0 mL of 0.20 M NaOH has been added.

◦ 1.6 × 10^–6M
◦ 1.3 × 10^–8M
◦ 3.9 × 10^–7M
◦ 7.8 × 10^–7M
◦ None of these are correct.

[Alyson.hiatt@yahoo.com]

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[Ruohan Liu]

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