Author Question: Can I determine exactly how much a marksman should lead a moving target? (Read 968 times)

Sandstorm

  • Sr. Member
  • ****
  • Posts: 268
I'm programming a small computer game and have run up on the following math problem:

Two objects exist on a two dimensional space.  One is a moving target, the other is a stationary shooter, firing at the target.  Assume that I know all of the following:

The exact location of the shooter and the target at any given point in time.
The distance between the shooter and the target at any given time.
The velocity and direction of motion of the target.
The velocity of the projectile.  (constant velocity)
All conditions are ideal: no friction, no changes in velocities or directions, no wind resistance, etc.

How can I determine what direction the shooter should fire in to hit the target at any given time?

I've been racking my brain for a couple of days, and can't figure this one out.  Any help is greatly appreciated.
I know the travel time will be equal for both the target and the projectile, and I can visualize how to do it on paper.  What I can't figure out is how to do it using a formula, which I need so I can code it properly.



camila

  • Hero Member
  • *****
  • Posts: 705
yes, here it goes:

Find the line the target moves on, then draw a line from the shooter dead straight, until it crosses the path of the target.  Then, use the velocities to determine where both the arrow and the target have exactly the same amount of travel time to the point.  Fire the arrow at the cross of the 2 paths when the target reaches its point where it will take exactly the same amount of time to reach the point as the arrow.



Related Topics

Need homework help now?

Ask unlimited questions for free

Ask a Question

federox

  • Sr. Member
  • ****
  • Posts: 308
determine time it takes for projectile to reach target (distance/speed), where the target will be after that time, and aim there.

If the target moves to/from the shooter, the distance travelled by the projectile will be different from what you assumed in the beginningso you might want to repeat the calculation one more time, or keep doing it untill convergence.



Jones

  • Full Member
  • ***
  • Posts: 145
Two ways to approach this.  One you may not have considered.  If your shooter is fixed, and your target is on a plane (x,y), what you may want to try is a change of coordinate.  This problem becomes fairly simple in polar coordinates, as the velocity of the projectile will depend on only one dimension.  The free parameter is simply the angle to 'aim' the projectile.  Anyhow, to solve this you integrate the velocities to get position equations.  Express each in terms of t, set equal to each other, then solve for the free parameter.  I would do it for you, but the procedure requires a analytic expression of the velocity.  Besides, if you follow the above, you can do it easily yourself.



curlz

  • Hero Member
  • *****
  • Posts: 538
ok the formula

if d1 is the distance between the shooter and the bullet
vb is the speed of the bullet
vt is the speed of the target
p1 is the targets original position
p2 is the targets new position when firing
you want to find p2

so vb/d1 will give you the time the bullet takes to get to the person

so you use that time and the velocity of the person to see how far they have gone from the origin, p1, and that is where the bullet should hit

p2 = (vb/d1)vt + p1



 

Did you know?

All adverse reactions are commonly charted in red ink in the patient's record and usually are noted on the front of the chart. Failure to follow correct documentation procedures may result in malpractice lawsuits.

Did you know?

Cocaine was isolated in 1860 and first used as a local anesthetic in 1884. Its first clinical use was by Sigmund Freud to wean a patient from morphine addiction. The fictional character Sherlock Holmes was supposed to be addicted to cocaine by injection.

Did you know?

The lipid bilayer is made of phospholipids. They are arranged in a double layer because one of their ends is attracted to water while the other is repelled by water.

Did you know?

Walt Disney helped combat malaria by making an animated film in 1943 called The Winged Scourge. This short film starred the seven dwarfs and taught children that mosquitos transmit malaria, which is a very bad disease. It advocated the killing of mosquitos to stop the disease.

Did you know?

There are more bacteria in your mouth than there are people in the world.

For a complete list of videos, visit our video library