Author Question: Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11 . David has a score of 52 ... (Read 184 times)

Yolanda · **on:** Jun 24, 2018

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11 . David has a score of 52 on Ms. Bond's test. Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6 . Steven has a score of 52 on Ms. Nash's test. Which student has the higher standardized score?
a. David's standardized score is -1.64 and Steven's standardized scores -2.00 . Therefore, David has the higher standardized score.
b. David's standardized score is -1.64 and Steven's standardized scores -2.00 . Therefore, Steven has the higher standardized score.
c. David's standardized score is 1.64 and Steven's standardized scores 2.00 . Therefore, Steven has the higher standardized score.
d. Cannot be determined with the information provided.

Question 2

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 9 . Steve has a score of 52 . Convert Steve's score to a z-score. (Round to two decimal places if necessary.)
a. 1.33

b. 58.2

c. 2
d. 1.33

Anna · **Reply #1 on:** Jun 24, 2018

Answer to Question 1

b
RATIONALE: David's standardized score is (52 70)/11 = 1.64 and Steven's standardized scores is (52 64)/6 = 2.00 . Therefore, David has the higher standardized score.

Answer to Question 2

d
RATIONALE: z-score = (sample mean)/standard deviation (52 64)/9 = 1.33