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Author Question: Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11 . David has a score of 52 ... (Read 144 times)

Yolanda

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on: Jun 24, 2018
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11 . David has a score of 52 on Ms. Bond's test. Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6 . Steven has a score of 52 on Ms. Nash's test. Which student has the higher standardized score?
 a. David's standardized score is -1.64 and Steven's standardized scores -2.00 . Therefore, David has the higher standardized score.
  b. David's standardized score is -1.64 and Steven's standardized scores -2.00 . Therefore, Steven has the higher standardized score.
  c. David's standardized score is 1.64 and Steven's standardized scores 2.00 . Therefore, Steven has the higher standardized score.
  d. Cannot be determined with the information provided.

Question 2

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 9 . Steve has a score of 52 . Convert Steve's score to a z-score. (Round to two decimal places if necessary.)
 a. 1.33
 
  b. 58.2
 
  c. 2
  d. 1.33


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Anna

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Reply #1 on: Jun 24, 2018
Answer to Question 1

b
RATIONALE: David's standardized score is (52  70)/11 = 1.64 and Steven's standardized scores is (52  64)/6 = 2.00 . Therefore, David has the higher standardized score.

Answer to Question 2

d
RATIONALE: z-score = (sample  mean)/standard deviation (52  64)/9 = 1.33


Yolanda

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Reply 2 on: Jun 24, 2018
Great answer, keep it coming :)

T4T

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Reply 3 on: Yesterday
Gracias!

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