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Author Question: A manufacturer of smartphone batteries will randomly select 20 batteries from the process each day ... (Read 226 times)

humphriesbr@me.com

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on: Jun 24, 2018
A manufacturer of smartphone batteries will randomly select 20 batteries from the process each day and count the number of defects. Historically, 4 of the batteries produced by this company have been defective.
 
  The following data represent the frequency of defective batteries from a random sample of 200 days.Number of Defective Frequency0 851 632 353 or more 17The manufacturer would like to test if the probability distribution for defective batteries follows the binomial distribution with p = 0.04 and n = 20 using  = 0.05. The expected number of days from this sample that no batteries from the batch of 20 are defective is ________.A) 15.08
  B) 37.74
  C) 71.70
  D) 75.48

Question 2

The ___________ criterion is the most optimistic method as well as the one with the highest level of risk.
 
  A) Hurwicz
  B) equally likely
  C) maximin
  D) maximax
Business Statistics ¦ Donnelly ¦ 2nd Edition
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braelync

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Reply #1 on: Jun 24, 2018
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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humphriesbr@me.com

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Reply 2 on: Jun 24, 2018
:D TYSM

nothere

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Reply 3 on: Yesterday
Wow, this really help

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