Medicare would like to test the hypothesis that the standard deviation for the monthly rate for a one-bedroom assisted-living facility is more than 400.
A random sample of 17 assisted living facilities had a standard deviation of 530. Using = 0.01, the conclusion for this hypothesis test would be that because the test statistic is ___________________ ________.
A) more than the critical value, we fail to reject the null hypothesis and conclude that the standard deviation for the monthly rates of one bedroom assisted-living facilities is more than 400
B) less than the critical value, we reject the null hypothesis and cannot conclude that the standard deviation for the monthly rates of one bedroom assisted-living facilities is more than 400
C) less than the critical value, we fail to reject the null hypothesis and cannot conclude that the standard deviation for the monthly rates of one bedroom assisted-living facilities is more than 400
D) more than the critical value, we fail to reject the null hypothesis and cannot conclude that the standard deviation for the monthly rates of one bedroom assisted-living facilities is more than 400
Question 2
A random sample of 25 roundtrip flights between Philadelphia and Dallas has an average airfare of 393.50 with a sample standard deviation of 50.30. The margin of error for a 90 confidence interval around this sample mean is ________.
A) 10.6
B) 14.1
C) 17.2
D) 22.9
Antibody techniques. (b) An ELISA to test for the presence of herpes simplex virus (HSV
Organic Test banks Carey 8th Edition
The Wug Test
Monitoring and Following Up on Laboratory Test Results
standard reduction potential (Eo), the greater the tendency of the oxidized form of a redox couple
Test-cross analysis of F1 plants