A couple wishes to determine the chances of having a blue-eyed ...

[mikaylakyoung]

A couple wishes to determine the chances of having a blue-eyed baby. Both parents have brown eyes, but have heterozygous gene pairs for eye color. Calculate the odds of their having a child with blue eyes.
 
  A.
  10
  B.
  20
  C.
  25
  D.
  50

Question 2

A nurse reads in a patient's chart that the patient has a condition caused by monosomy X. What can the nurse conclude about this patient?
 
  A.
  Female with one missing X chromosome
  B.
  Female with very feminine features
  C.
  Male with one extra X chromosome
  D.
  Male with very feminine features

[Bsand8]

Answer to Question 1

ANS: C
Each parent has a heterozygous gene pair for brown eyes, which means that each parent has one blue gene and one brown gene. Using a Punnett square, one can calculate the odds of their having a blue-eyed baby to be 25.

Answer to Question 2

ANS: A
A monosomy condition is one in which only one of the paired chromosomes is present. In this case, the patient would have one or more cells with one X chromosome and nothing else. Turner's syndrome is the most common example of this defect; children born with this syndrome are female and exhibit juvenile external genitalia, underdeveloped ovaries, short stature, webbing of the neck, and possible intellectual deficits and cardiac disorders.