Author Question: You have collected data for a cross-section of countries in two time periods, 1960 and 1997, say. ... (Read 99 times)

arivle123 · **on:** Jun 29, 2018

You have collected data for a cross-section of countries in two time periods, 1960 and 1997, say.

Your task is to find the determinants for the Wealth of a Nation (per capita income) and you believe that there are three major determinants: investment in physical capital in both time periods (X1,T and X1,0), investment in human capital or education (X2,T and X2,0), and per capita income in the initial period
(Y0). You run the following regression:

ln(YT) = 0 + 1X1,T + 2X1,0 + 3X2,T + 4X1,0 + ln(Y0) + uT

One of your peers suggests that instead, you should run the growth rate in per capita income over the two periods on the change in physical and human capital. For those results to be a parsimonious presentation of your initial regression, what three restrictions would have to hold? How would you test for these? The same person also points out to you that the intercept vanishes in equations where the data is differenced. Is that true?
What will be an ideal response?

Question 2

A nonlinear function

A) makes little sense, because variables in the real world are related linearly.
B) can be adequately described by a straight line between the dependent variable and one of the explanatory variables.
C) is a concept that only applies to the case of a single or two explanatory variables since you cannot draw a line in four dimensions.
D) is a function with a slope that is not constant.

Heffejeff · **Reply #1 on:** Jun 29, 2018

Answer to Question 1

Answer: The regression using growth rates is as follows:

ln(YT) - ln(Y0) = 0 + 1(X1,T - X1,0 )+ 3(X2,T - X1,0)+ ( 5- 1) ln(Y0) + uT

For this to be a parsimonious presentation of the initial regression, the following two restrictions must hold: 1 = -2, and 3 = -4.The use of an F-test is required here to test the restrictions simultaneously. The intercept is still present in the equation, and the assertion therefore cannot be true.

Answer to Question 2

Answer: C