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Author Question: A client is receiving 1 liter of Dextrose 5 and 0.45 normal saline with 40 mEq KCL infusing at 20 ... (Read 49 times)

leo leo

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on: Jul 3, 2018
A client is receiving 1 liter of Dextrose 5 and 0.45 normal saline with 40 mEq KCL infusing at 20 gtts/min. The drop factor is 15 gtts/mL. How much KCL is the client receiving each minute?
 
  1. 0.053 mEq
  2. 0.53 mEq
  3. 5.3 mEq
  4. 53 mEq

Question 2

What is the correct conversion of 2300 (military time) to standard time?
 
  What will be an ideal response?


akudia

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Reply #1 on: Jul 3, 2018
Answer to Question 1

1

Rationale 1: mEq/min = 40 mEq/1000 mL x 1 mL/15 gtts x 20 gtt/1 min. Multiply the numerators and then divide by the denominators. The client is receiving 0.053 mEq of KCL per minute.

Answer to Question 2

11:00 p.m.
11:00 P.M.
11:00 pm


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