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Author Question: For a substance to be a mineral, it must be a naturally occurring inorganic solid with a definite ... (Read 92 times)

sc00by25

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For a substance to be a mineral, it must be a naturally occurring inorganic solid with a definite chemical composition and an ordered atomic arrangement.
 
  For each of the following substances, determine whether or not it is a mineral. If it is not a mineral, list all of the mineral properties that do not apply to it.
  What will be an ideal response?

Question 2

You finish your canned drink and get ready to throw it out. A garbage can is right nearby, but the recycling bin is a few more steps.
 
  Should you bother to recycle aluminum cans? Does it really make a difference? Remember that most electrical energy in the U.S. is generated from fuels that contribute to global climate change. So, when you recycle an aluminum can, about how much energy is saved compared to the amount needed to make a new can? A) 10 to 20
  B) 30 to 40
  C) 50 to 60
  D) 85 to 95



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iceage

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Answer to Question 1

a. amber: NO organic solid; no definite chemical composition; no ordered atomic arrangement.
b. beer: NO not naturally occurring; organic solid; no definite chemical composition; no ordered atomic arrangement.
c. calcite: YES
d. diamond: YES
e. emerald: YES
f. plagioclase feldspar: YES
g. glacial ice: YES
h. halite: YES
i. ice cubes from an ice machine: YES (because ice is a naturally occurring mineral)
j. rock candy: NO not naturally occurring; organic solid; no definite chemical composition; no ordered atomic arrangement.
k. kryptonite: NO not naturally occurring; organic solid; no definite chemical composition; no ordered atomic arrangement.
l. cubic zirconia: NO not naturally occurring; organic solid; no definite chemical composition; no ordered atomic arrangement.
m. mineral oil: NO not naturally occurring; organic solid; no definite chemical composition; no ordered atomic arrangement.
n. muscovite: YES
o. obsidian: NO no ordered atomic arrangement.

Answer to Question 2

D




sc00by25

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Reply 2 on: Jul 16, 2018
Gracias!


mcarey591

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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