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Author Question: Suppose that daycare costs are normally distributed with a mean equal to 10,000 a year and a ... (Read 56 times)

bclement10

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on: Jul 24, 2018
Suppose that daycare costs are normally distributed with a mean equal to 10,000 a year and a standard deviation equal to 2,000. What percentage of daycare centers will cost between 5,600 and 12,800?

Question 2

Suppose that daycare costs are normally distributed with a mean equal to 10,000 a year and a standard deviation equal to 2,000. What percentage of daycare centers will cost between 7,400 and 11,000?


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janeli1

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Reply #1 on: Jul 24, 2018
Answer to Question 1

P(5,600 < x < 12,800) = P(-2.20 < z < 1.40) = 0.4861 + 0.4192 = 0.9053

Answer to Question 2

P(7,400 < x < 11,000) = P(-1.30 < z < 0.50) = 0.4032 + 0.1915 = 0.5947


bclement10

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Reply 2 on: Jul 24, 2018
:D TYSM

kswal303

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Reply 3 on: Yesterday
Gracias!

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