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Author Question: When an object is placed 118 cm from a thin diverging lens, its image is found to be 59 cm from the ... (Read 35 times)

natalie2426

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on: Jul 29, 2018
When an object is placed 118 cm from a thin diverging lens, its image is found to be 59 cm from the lens. The lens is removed, and replaced by a thin converging lens whose focal length has the same magnitude as the diverging lens.
 
  This second lens is at the original position of the first lens. Where is the image of the object now?

Question 2

An object is 50 cm from a concave mirror with radius of curvature of magnitude 60 cm. What is the lateral magnification produced by the mirror?
 
  A) +0.40
  B) +0.70
  C) +1.5
  D) -0.70
  E) -1.5
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Chou

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Reply #1 on: Jul 29, 2018
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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natalie2426

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Reply #2 on: Jul 29, 2018
Thank you!


Chou

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Reply #3 on: Jul 29, 2018
Always glad to help...


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