The energy stored in a coil of self-inductance, L, and traversed ...

[j.rubin]

The energy stored in a coil of self-inductance, L, and traversed by current I, is E1. A second coil is made with the same length of wire, but its radius is twice the radius of the first coil and it is twice as long as the first coil.
 
  If the second coil also has twice the current of the first coil, how does the energy stored in the first coil, E1, compare to the energy stored in the second coil, E2? A) E1 = E2
  B) E1 = E2/8
  C) E1 = 4E2
  D) E1 = E2/2
  E) E1 = E2/4

Question 2

A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a 60.0 N force for the first 6.88 m, at which time he begins to tire.
 
  The force he exerts then starts to decrease linearly from 60.0 N to 0.00 N across the remaining 6.88 m. How much total work did the person do on the box? A) 619 J
  B) 826 J
  C) 495 J
  D) 925 J

[TheNamesImani]

Answer to Question 1

B

Answer to Question 2

A

[j.rubin]

Gracias!

[amandanbreshears]

TYSM