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Author Question: Which is NOT an axiom put forth by Lloyd Shapely? a.If x is the Shapely value vector for game v and ... (Read 64 times)

drink

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on: Aug 1, 2018
Which is NOT an axiom put forth by Lloyd Shapely?
  a.If x is the Shapely value vector for game v and y is the Shapely value vector for game , then game (v + ) has a Shapely value vector of x-y.
  b.If v(S-i) = v(S), then for all S xi=0.
  c..
  d.Relabeling of players interchanges the player's rewards.

Question 2

A solution for an n-person game lies in ________.
  a.coalition forming.
  b.imputation.
  c.the core.
  d.domination.


carolinefletcherr

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Reply #1 on: Aug 1, 2018
Answer to Question 1

correct: a

Answer to Question 2

correct: c


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