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Author Question: Evaluate y: y = (3x2 - x - 1) - (5 - 2x - x2) for x = -3 (Read 38 times)

clmills979

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on: Jun 6, 2019

Question 1

Evaluate: 4x2 - 10xy - 8y2 for x = -3, y = 5

Question 2

Evaluate y: y = (3x2 - x - 1) - (5 - 2x - x2) for x = -3
Contemporary Business Mathematics with Canadian Applications ¦ Hummelbrunner, Halliday, Coombs ¦ 11th Edition
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Marked as best answer by clmills979 on Jun 6, 2019

jordangronback

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Reply #1 on: Jun 6, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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clmills979

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Reply #2 on: Jun 6, 2019
Thank you!


jordangronback

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Reply #3 on: Jun 6, 2019
Always glad to help...


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