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Author Question: Suppose that W is a random variable. Given that P(W 3) = 0.625, find P(W > 3). (Read 508 times)

sjones

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on: Apr 7, 2020

Question 1

Use the special addition rule and the following probability distribution to determine P(6 < X ≤ 8).
 x                5          6          7          8          9          10          11    
P(X = x)    0.05    0.05     0.20     0.15     0.15      0.10        0.30
◦ 1.00
◦ 0.35
◦ 0.40
◦ 0.45

Question 2

Suppose that W is a random variable. Given that P(W ≤ 3) = 0.625, find P(W > 3).
◦ 0
◦ 0.375
◦ 0.625
◦ 3
Introductory Statistics ¦ Weiss ¦ 10th Edition
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Marked as best answer by sjones on Apr 7, 2020

dawsa925

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Reply #1 on: Apr 7, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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maxienne

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Reply #2 on: Feb 15, 2022
THANK YOU


brandon osmond

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Reply #3 on: Feb 17, 2022
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