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Author Question: A uniform rod is 2.0 m long. It is hinged to a wall at its left end, and held in a horizontal ... (Read 65 times)

jwb375

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on: Oct 11, 2019

Question 1

A cinder block of mass m = 4.0 kg is hung from a nylon string that is wrapped around a frictionless pulley having the shape of a cylindrical shell, as shown in the figure. If the cinder block accelerates downward at 4.90 m/s2 when it is released, what is the mass M of the pulley?



◦ 6.0 kg
◦ 8.0 kg
◦ 10 kg
◦ 4.0 kg
◦ 2.0 kg

Question 2

A uniform rod is 2.0 m long. It is hinged to a wall at its left end, and held in a horizontal position at its right end by a vertical very light string, as shown in the figure. What is the angular acceleration of the rod at the moment after the string is released if there is no friction in the hinge?



◦ 7.4 rad/s2
◦ 11 rad/s2
◦ 3.3 rad/s2
◦ 15 rad/s2
◦ It cannot be calculated without knowing the mass of the rod.
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Marked as best answer by jwb375 on Oct 11, 2019

efwsefaw

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jwb375

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Reply 2 on: Oct 11, 2019
Excellent

EAN94

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Reply 3 on: Yesterday
Wow, this really help

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