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Author Question: A 3.7-kg block on a horizontal frictionless surface is attached to an ideal spring whose force ... (Read 75 times)

formula1

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Question 1

A 0.39-kg block on a horizontal frictionless surface is attached to an ideal spring whose force constant (spring constant) is The block is pulled from its equilibrium position at x = 0.000 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the position of the block is its kinetic energy is closest to
◦ 1.0 J.
◦ 1.1 J.
◦ 0.95 J.
◦ 0.84 J.
◦ 0.90 J.

Question 2

A 3.7-kg block on a horizontal frictionless surface is attached to an ideal spring whose force constant (spring constant) is The block is pulled from its equilibrium position at x = 0.000 m to a position x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. The maximum elastic potential energy of the system is closest to
◦ 1.7 J.
◦ 1.6 J.
◦ 1.8 J.
◦ 1.3 J.
◦ 1.4 J.


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Marked as best answer by formula1 on Oct 11, 2019

brbarasa

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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formula1

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Reply 2 on: Oct 11, 2019
Wow, this really help


upturnedfurball

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

 

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