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Author Question: A 5.0-F and a 12.0-F capacitor are connected in series, and the series arrangement is connected in ... (Read 76 times)

WWatsford

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on: Oct 11, 2019

Question 1

A 5.0-μF, a 14-μF, and a capacitor are connected in parallel.  How much capacitance would a single capacitor need to have to replace the three capacitors?
◦ 40 μF
◦ 14 μF
◦ 5.0 μF
◦

Question 2

A 5.0-μF and a 12.0-μF capacitor are connected in series, and the series arrangement is connected in parallel to a capacitor.  How much capacitance would a single capacitor need to replace this combination of three capacitors?
◦ 38 μF
◦ 33 μF
◦ 13 μF
◦ 16 μF
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Marked as best answer by WWatsford on Oct 11, 2019

mochi09

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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WWatsford

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Reply #2 on: Oct 11, 2019
Thanks


mochi09

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Reply #3 on: Oct 11, 2019
Welcome :)


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