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Author Question: If 100. mL of 0.400 mol L-1 Na2SO4 is added to 200. mL of 0.600 mol L-1 NaCl, what is the ... (Read 111 times)

jasdeep_brar

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Question 1

How many millilitres of 0.200 mol L-1 FeCl3 are needed to react with an excess of Na2S to produce 1.38 g of Fe2S3 if the percent yield for the reaction is 65.0%?

3Na2S(aq) + 2FeCl3(aq) → Fe2S3(s) + 6NaCl(aq)

◦ 102 mL
◦ 51.1 mL
◦ 43.1 mL
◦ 25.5 mL

Question 2

If 100. mL of 0.400 mol L-1 Na2SO4 is added to 200. mL of 0.600 mol L-1 NaCl, what is the concentration of Na+ ions in the final solution? Assume that the volumes are additive.
◦ 0.534 mol L-1
◦ 0.667 mol L-1
◦ 1.40 mol L-1
◦ 1.00 mol L-1


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Marked as best answer by jasdeep_brar on Nov 18, 2019

6ana001

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jasdeep_brar

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Reply 2 on: Nov 18, 2019
:D TYSM


adammoses97

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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